Question

(4x-3)^2=-9



X^2+6x+9=5

Answer 1

(4x-3)²=-9
16x²-24x+9+9=0
16x²-24x+18=0

Δ=(-24)²-4.16.18
Δ=576-1152=-576

x'=-(-24)+√-576/2.16=24+√-576/32

x"=-(-24)-√-576/2.16=24-√-576/32




x²+6x+9=5
x²+6x+9-5=0
x²+6x+4=0

Δ=6²-4.1.4
Δ=36-16=20

x'=-6+√20/2.1=-6+2√5/2=-3+√5

x'=-6-√20/2.1=-6-2√5/2=-3-√5