Question

(1/$\sqrt[3]{4}$)$x^{}$=16

Answer 1

$\left(\dfrac{1}{\sqrt[3]{4}}\right)^x=16\\\\\left(\dfrac{1}{4^{\frac{1}{3}}}\right)^x=4^2\\\\ (4^{-\frac{1}{3}})^x=4^2\\\\ 4^{-\frac{x}{3}}=4^2\\\\-\dfrac{x}{3}=2\\\\-x=6\\\\ \boxed{x=-6}$

Answer 2

    4^-x/3 = 4^2

       - x  =  2 
         3
        - x = 6 (-1)

           x = 6