Question

Resolva as seguintes equações :
A)x-15=18
B)2x-32=68
C)4x-29=271
D)18x-36=24+8x
E)12x-30=6x+6
F)4x+10=2x+38

Answer 1

Explicação passo-a-passo:

$\blue {{ _{\heartsuit} } \heartsuit_{\heartsuit} } \: \: \mathsf {OI, TUDO \: \: J\acute{O}IA \: ? \: \:\blue {{ _{\heartsuit} } \heartsuit_{\heartsuit} } }$

a)

$\mathtt{x - 15 = 18} \\ \mathtt{x = 18 + 15} \\ \red {\mathtt{x = 33}}$

b)

$\mathtt{2x - 32 = 68} \\ \mathtt{2x = 68 + 32} \\ \mathtt{2x = 100} \\ \mathtt{x = \frac{100}{2} } \\ \red {\mathtt{x = 50}}$

c)

$\mathtt{4x - 29 = 271} \\ \mathtt{4x = 271 + 29} \\ \mathtt{4x = 300} \\ \mathtt{x = \frac{300}{4} } \\ \red {\mathtt{x = 75}}$

d)

$\mathtt{18x - 36 = 24 + 8x} \\ \mathtt{18x - 8x = 24 + 36} \\ \mathtt{10x = 24 + 36} \\ \mathtt{10x = 60} \\ \mathtt{x = \frac{60}{10} } \\ \red {\mathtt{x = 6}}$

e)

$\mathtt{12x - 30 = 6x + 6} \\ \mathtt{12x - 6x = 6 + 30} \\ \mathtt{6x = 6 + 30} \\ \mathtt{6x = 36} \\ \mathtt{x = \frac{36}{6} } \\ \red {\mathtt{x = 6}}$

f)

$\mathtt{4x + 10 = 2x + 38} \\ \mathtt{4x - 2x = 38 - 10} \\ \mathtt{2x = 28} \\ \mathtt{x = \frac{28}{2} } \\ \red {\mathtt{x = 14}}$

$\mathcal{ATT : ARMANDO}$