(50 PONTOS) Um pino tem a forma triangular de medidas 4mm, 5mm e 6mm. Ele deve ser encaixado exatamente num furo circular. Calcule o diâmetro desse furo. (Quero o cálculo).
Respostas
respondido por:
7
a ⋅ b ⋅ c
R =
√ [ (a + b + c) ⋅ (−a + b + c) ⋅ (a − b + c) ⋅ (a + b − c) ]
Onde.
R: circunraio
a, b e c: medidas dos lados do triângulo.
4 ⋅ 5 ⋅ 6
R =
√ [ (4 + 5 + 6) ⋅ (−4 + 5 + 6) ⋅ (4 − 5 + 6) ⋅ (4 + 5 − 6) ]
120
R =
√ [ ( 15 ) ⋅ ( 7 ) ⋅ ( 5 ) ⋅ ( 3 ) ]
120
R =
√ [ ( 15 ) ⋅ ( 7 ) ⋅ ( 15 ) ]
120
R =
√ [ ( 15 )² ⋅ ( 7 ) ]
120
R =
15 ⋅ √ ( 7 )
8
R = mm
√ ( 7 )
R =
√ [ (a + b + c) ⋅ (−a + b + c) ⋅ (a − b + c) ⋅ (a + b − c) ]
Onde.
R: circunraio
a, b e c: medidas dos lados do triângulo.
4 ⋅ 5 ⋅ 6
R =
√ [ (4 + 5 + 6) ⋅ (−4 + 5 + 6) ⋅ (4 − 5 + 6) ⋅ (4 + 5 − 6) ]
120
R =
√ [ ( 15 ) ⋅ ( 7 ) ⋅ ( 5 ) ⋅ ( 3 ) ]
120
R =
√ [ ( 15 ) ⋅ ( 7 ) ⋅ ( 15 ) ]
120
R =
√ [ ( 15 )² ⋅ ( 7 ) ]
120
R =
15 ⋅ √ ( 7 )
8
R = mm
√ ( 7 )
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