Question

1- Resolva o logaritmo

Log7 (3x - 4) - Log7 x =0

Answer 1

$log_7\: 3x - 4 - log_7\: x = 0 \\ log_7\: [(3x - 4)x] = 0 \\ 3x^2 - 4x = 7^0 \\ 3x^2 - 4x - 1 = 0$

x' = 4 + 2√7/6

x" = 4 - 2√7/6