• Matéria: Matemática
  • Autor: Luizaberner12
  • Perguntado 8 anos atrás

Dada a Matriz: ....
Determine a matriz X tal que:

Anexos:

Respostas

respondido por: Rich0031
6
X + 3A - B = 2C \\ X = 2C - 3A + B \\ \\ X = 2  \left[\begin{array}{ccc}1&3&5\\4&2&3\end{array}\right] - 3  \left[\begin{array}{ccc}- 3&4&1\\0&2&- 2\end{array}\right] +   \left[\begin{array}{ccc}1&1&0\\- 1&1&2\end{array}\right] \\ \\ X =   \left[\begin{array}{ccc}2&6&10\\8&4&6\end{array}\right] -   \left[\begin{array}{ccc}- 9&12&3\\0&6&- 6\end{array}\right] +   \left[\begin{array}{ccc}1&1&0\\- 1&1&2\end{array}\right]
 X =   \left[\begin{array}{ccc}2&6&10\\8&4&6\end{array}\right] -   \left[\begin{array}{ccc}- 8&13&3\\- 1&7&- 4\end{array}\right] =   \left[\begin{array}{ccc}10&- 7&7\\9&5&10\end{array}\right]


2B + C + X = A \\X = - 2B - C + A \\ \\  X = (- 2)  \left[\begin{array}{ccc}1&1&0\\- 1&1&2\end{array}\right] -    \left[\begin{array}{ccc}1&3&5\\4&2&3\end{array}\right] +   \left[\begin{array}{ccc}- 3&4&1\\0&2&- 2\end{array}\right] \\ \\ X =   \left[\begin{array}{ccc}- 2&- 2&0\\2&- 2&- 4\end{array}\right] -   \left[\begin{array}{ccc}- 2&7&6\\4&4&1\end{array}\right] =   \left[\begin{array}{ccc}0&- 9&- 6\\- 2&- 6&- 5\end{array}\right]

Faça as proximas

Luizaberner12: muito obrigada!
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