Question

Metodo da substituicao
2x-5y=0
5x+3y=4
Me ajudem prfv

Answer 1

I)2x-5y=0
2x=5y
x=5y/2
II)5x+3y=4
5[5y/2]+3y=4
25y/2+3y=4 [Multiplica tudo por 2]
2*25y/2+2*3y=2*4
25y+6y=8
31y=8
y=8/31
x=5/2 * 8/31
x=40/62
x=20/31