Question

Determine a resistencia equivalente, vista dos pontos A e B no circuito

Answer 1

$\frac{36.12}{12+36}\\ \frac{36.12}{48} \\ \frac{36.12}{12.4} \\ \frac{36}{4} = 9$
9Ω

$9+3=12$
12Ω

$\frac{24.8}{24+8} \\ \frac{24.8}{32} \\ \frac{24.8}{2.16} \\ \frac{12}{2} = 6$
6Ω

$\frac{12.6}{12+6} \\ \frac{12.6}{18} \\ \frac{12.6}{3.6} \\ \frac{12}{3} =4$
4Ω

$6+4=10$
10Ω

$25+15=40$
40Ω

$\frac{40.10}{40+10} \\ \frac{40.10}{50} \\ \frac{40.10}{5.10} \\ \frac{40}{5}=8$
Req=8Ω