Question

2× ao quadrado + 5x +1 =0




3x ao quadrado = 7x+1

Answer 1

2x^2+5x+1=0
Δ=b^2-4.a.c
Δ=25-8
Δ=17

x1=$\frac{-5+ \sqrt{17} }{4}$
x2=$\frac{-5- \sqrt{17} }{4}$
S={ $\frac{-5+ \sqrt{17} }{4}$,$\frac{-5- \sqrt{17} }{4}$ }

3x^2=7x+1
3x^2-7x-1=0
Δ=7^2-4.(+3).(-1)
Δ=49+12
Δ=61

x1=$\frac{7+ \sqrt{61} }{6}$
x2=$\frac{7+ \sqrt{61} }{6}$
S={ $\frac{7+ \sqrt{61} }{6}$,$\frac{7+ \sqrt{61} }{6}$ }