Question

2 Log x = Log 2 + Log x

Answer 1

2 log x = log 2 + log x

log x² = log 2 . x

x² = 2x

x² - 2x = 0

Δ = b² - 4ac

Δ = 4

x = -b +/- √Δ / 2a

x = 2 +/- 2 / 2

x' = 2 + 2 / 2 = 4/2 = 2

x'' = 2 - 2 2 = 0/2 = 0

Sendo que x > 2

Logo, x = 2