Question

calcule a area de um trapezio de altura 90 cm e bases 1m e 12 dm

Answer 1

12dm=1,20m
90cm=0,90m

A=(B+b)*h/2

A=(1+1,20)*0,90/2
A=2,20*0,90/2
A=1,98/2
A=0,99
Resposta: 0,99m²

Answer 2

Dados
h=90cm=0,9m
B=12dm=1,2m
b=1m

$A= \frac{B+b}{2} *h= \frac{1,2+1}{2} *0,9= \frac{2,2}{2}*9= 1,1*0,9=0,99m^{2}$