Question

5x ao quadrado -2x+2=0

Answer 1

$x^{2} - 2x + 2 = 0$



a=5, b=−2, c=2

Δ=b²−4ac
Δ=(−2)²−4*(5)*(2)
Δ=4−40
Δ= −36

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-2) \pm \sqrt{-36}}{2*5} \\ \\ \\ x = \dfrac{2 \pm \sqrt{36}*i}{10} \\ \\ \\ x = \dfrac{2 \pm 6*i}{10} \\ \\ \\ x' = \dfrac{2 + 6*i}{10} \\ \\ \\ x' = \dfrac{1 + 3*i}{5} \\ \\ \\ x'' = \dfrac{2 - 6*i}{10} \\ \\ \\ x'' = \dfrac{1 - 3*i}{5}$


S = {$\dfrac{1 + 3*i}{5} \ , \ \ \dfrac{1 - 3*i}{5}$}