Question

se A^2= 99^6, B^3= 99^7 e C^4=99^8, então (A.B.C)^12 vale:?

Answer 1

se A^2= 99^6, B^3= 99^7 e C^4=99^8, então (A.B.C)^12 vale:?

A=99^(6/2) = 99^3
B =99^(7/3)
C = 99^(8/4) = 99^2

(A.B.C)^(3+7/3+2) = (A.B.C)^(22/3)

logo não vale

(A.B.C)^12