Question

agradeço quem responder

Answer 1

a) $\frac{(7^2)^3}{(7^3)^2} = \frac{7^{2*3}}{7^{3*2}} = \frac{7^6}{7^6} = 7^{6-6} = 7^0 = 1$

b) $\frac{(3*5^2)^3}{(3^2*5)^2} = \frac{3^3*(5^2)^3}{(3^2)^2*5^2} = \frac{3^2*5^{2*3}}{3^{2*2}*5^2} = \frac{3^2*5^6}{3^4*5^2} = 3^{2-4}*5^{6-2} = 3^{-2} * 5^4 = \frac{5^4}{3^2}$