Question

como resolver essa equacao ?
3 [10+(3w-1)-(4-w)]=5 (w+10)

Answer 1

3[10+(3w-1)-(4-w)] = 5(w+10)
[30+(9w-3)-(12-3w)] = (5w+50)
30+9w-3-12+3w = 5w+50
(9w+3w) + (30-3-12) = 5w+50
12w + 15 = 5w + 50
12w + 15 - 5w = 5w + 50 - 5w
7w + 15 = 50
7w + 15 - 15 = 50 - 15
7w = 35
7w / 7 = 35 /7
w = 35/7 = 5
w = 5