Question

quero saber como eu monto essa conta,e o resultado de x2-6x+9=0

Answer 1

$x^{2} - 6x + 9 = 0$

Use a formula de Bháskara:

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1, b=−6, c=9

Δ=b²−4ac
Δ=(−6)²−4*(1)*(9)
Δ=36−36
Δ=0

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-6) \pm \sqrt{0}}{2*1} \\ \\ \\ x = \dfrac{6 \pm 0}{2} \\ \\ \\ x' = \dfrac{6 + 0}{2} \\ \\ \\ x' = \dfrac{6}{2} \\ \\ \\ x' = 3 \\ \\ \\ x'' = \dfrac{6 - 0}{2} \\ \\ \\ x'' = \dfrac{6}{2} \\ \\ \\ x'' = 3$


S  = {3}