Question

Calcule o
nono termo da PA (8,4,0,-4,8...)

Answer 1

r = -4
a1 = 8
P(a,...,b)
n = 1 + [(b9-a)/r)]
9 = 1 + [(b9-8)/-4]
8 = (b9-8) / -4
8*(-4) = (b9-8)
-32 = b9 - 8
-32 + 8 = b9
b9 = -24