Question

Considerando log 2=0,3; log 3=0,48 e log 5=0,7, use as propriedades operatórias e calcule o valor dos seguintes logaritmos:

a. log_{4} 192

Answer 1

$3 + \frac{1}{2} \times log2(3)$

Answer 2

$\log_4192= \\ \\ mudar~~para~~base~~10 \\ \\ \frac{log192}{log4} = \\ \\ \frac{log2^6.3}{log2^2} = \frac{log2^6+log3}{log2^2} = \\ \\ \frac{6log2+log3}{2log2} = \\ \\ \frac{6.(0,3)+0,48}{2.(0,3)} = \frac{1,8+0,48}{0,6} = \frac{2,28}{0,6} =3,8$