Question

formada Z sobre o resultado, ou então abrindo G(s)/s em frações parciais.



G left parenthesis s right parenthesis equals fraction numerator s plus 3 over denominator s plus 1 end fraction



Realize o processo de discretização do sistema a seguir utilizando um segurador de ordem zero para T = 1.

Assinale a resposta correta:

Escolha uma:
a. G left parenthesis z right parenthesis equals fraction numerator z minus 0 comma 1031 over denominator z plus 0 comma 3671 end fraction.
b. G left parenthesis z right parenthesis equals fraction numerator 2 z plus 0 comma 1096 over denominator z minus 0 comma 3699 end fraction.
c. G left parenthesis z right parenthesis equals fraction numerator 2 z minus 0 comma 2036 over denominator z plus 0 comma 2679 end fraction.
d. G left parenthesis z right parenthesis equals fraction numerator 2 z minus 0 comma 1036 over denominator z minus 0 comma 3679 end fraction.
e. G left parenthesis z right parenthesis equals fraction numerator z minus 0 comma 1836 over denominator z minus 0 comma 3689 end fraction.

Answer 1

G(z)= (2Z-0,2036)/(Z+0,2679) - INCORRETA!

Answer 2

G(z) = 2z - 0,1036 / z - 0,3979