Question

resolva x^2-4kx+4k^2- m^2=0

Answer 1

delta > 0 kx² -2(k+1)x + (k+5) = 0 a = k b = (- 2k-2) c = (k+5) Δ = b² - 4ac> 0 (-2k-2)² - 4k.(k+ 5) > 0 4k² + 8k + 4 - 4k² - 20k > 0 -12k + 4 > 0