Question

dados log 2 = 0,3010 log 3 = 0,4771; calcule log 2 /3 e log (2.3)

Answer 1

$log_{(a/b)}=log_{a}-log_{b}\\ log_{(2/3)}=log_{2}-log_{3}\\ log_{(2/3)}=0,3010-0,4771= -0,1761//\\\\ log_{(a*b)}=log_{a}+log_{b}\\ log_{(2/3)}=log_{2}+log_{3}\\ log_{(2/3)}=0,3010+0,4771=0,7781//$