Question

resolva a expressão $\frac{[2 ^{9} :(2.2 ^{2} ) ^{3} ] ^{-3} }{2}$

Answer 1

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$[ \frac{2^9\div(2.2^2)^3}{2} ]^{-3}=$

$[ \frac{2^9\div(2^{1+2})^3}{2} ]^{-3}= [tex][ \frac{2^9\div(2^3)^3}{2} ]^{-3}=$

$[ \frac{2^9\div2^9}{2} ]^{-3}= \\ \\ ( \frac{2^{9-9}}{2} )^{-3}= \\ \\ ( \frac{2^0}{2} )^{-3}= \\ \\ (2^0\div2)^{-3}= \\ \\( 2^{0-1})^{-3}= \\ \\ (2^{-1})^{-3}= \\ \\ 2^3=8$