Question

Encontre os limites indicados, se existirem

lim(3x²-5x+2)=
x⇒3

lim (x∧5-6x∧4+7)=
x⇒0

Answer 1

lim(3x²-5x+2)=  3*3²-5*3+2 =27-15+2 = 14
x⇒3

lim (x^5-6x^4+7)= =0-0+7=7
x⇒0