Question

x²-5x+6=0 me ajudem ?

Answer 1

Δ=b²-4.a.c       
Δ=5²-4.1.6           DISCRIMINANTE.
Δ=25-24
Δ=1
 
x=-b₊₋√Δ  /2.a
x=-(-5)₊₋√1 /2.1              5+1/2=3
x=5₊₋1 /2           Então >
                                       5-1/2=2   
Solução: s= {3,2}

Answer 2

Resposta:

S = {2, 3}

Explicação passo-a-passo:

$x^{2}-5x+6=0$

$a=1\\b=(-5)\\c=6$

$\Delta=b^{2} -4ac\\\Delta=(-5)^{2}-4\times1\times6\\\Delta=25-24\\\Delta=1$

$x=\frac{-b\pm\sqrt{\Delta} }{2a} \\\\x=\frac{-(-5)\pm\sqrt{1} }{2\times1} \\\\x=\frac{5\pm1}{2}$

$x_{1} =\frac{5+1}{2} =\frac{6}{2} =3\\\\x_{2} =\frac{5-1}{2} =\frac{4}{2} =2$