Question

4+x(x+3)-40=0 bhaskara

Answer 1

4 - 40 +x.(x+3) = 0
-36 + x² + 3x = 0
(organizando)
x² + 3x - 36 = 0

A= 1
B= 3
C= 36

Δ = delta
Δ= b² - 4.a.c
Δ= 3² - 4.1. -36
Δ= 9 + 144
Δ= 153

x= $\frac{-b +- \sqrt{delta}}{2.a}$
x1= $\frac{-3 +\sqrt{153} }{2.1}$
x1= $\frac{-3 + \sqrt{ 3^{2}. 17 } }{2}$
x1= $\frac{-3 +3 \sqrt{17} }{2}$

X2=$\frac{-3 -3 \sqrt{17} }{2}$

Answer 2

4+X+3X-40=0
X+3X=0-4+40
4X=-4+40
4X=36
X=36/4
X=9