• Matéria: Matemática
  • Autor: leonardocastilp8mebo
  • Perguntado 8 anos atrás

Resolva a expressão:
a) (-5)-(-3)+(+2)-(+1)+(-8)
B) (12-2)-3+(8+7-5)
C) 1/5+ {[4/9:(1/2x2/4-1/9)]}
D) (4-4/5):(9+1/3)
E) 0,0006.10elevado5/ 0,096.10elevado3=

Por favor preciso dos cálculos

Respostas

respondido por: MATHSPHIS
3
A) (-5)-(-3)+(+2)-(+1)+(-8)=
-5+3+2-1-8=-9
 
B) (12-2)-3+(8+7-5)=
10-3+10=17

C) 
\frac{1}{5}+ \{[\frac{4}{9}\div (\frac{1}{2}*\frac{2}{4}-\frac{1}{9})]\}=\\
\\
\frac{1}{5}+ \{[\frac{4}{9}\div (\frac{1}{4}-\frac{1}{9})]\}=\\
\\
\frac{1}{5}+ \{[\frac{4}{9}\div (\frac{9-4}{36})]\}=\\
\\
\frac{1}{5}+ \{[\frac{4}{9}\div (\frac{5}{36})]\}=\\
\\
\frac{1}{5}+ \{[\frac{4}{9}* \frac{36}{5}]\}=\\
\\
\frac{1}{5}+ \frac{16}{5}=\frac{17}{5}


D) 
(4-\frac{4}{5})\div(9+\frac{1}{3})=\\
\\
(\frac{20-4}{5})\div \frac{27+1}{3})=\\
\\
\frac{21}{5}\div\frac{28}{3}=\\
\\
\frac{21}{5}* \frac{3}{28}=\frac{9}{20}


E) 
0,0006.10^5 \div 0,096.10^3=6.10^9\div9,6.10^{11}=\\
\\
\frac{6}{9,6}.10^{2}=0,625.10^2=62,5
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