Question

Insira treze meios aritméticos entre 4 e 60? Alguém

Answer 1

a₁ = 4
a₁₅ = 60

a₁₅ = a₁ + 14r
60 = 4 + 14r
14r = 60 - 4
14r = 56
r = 56/14
r = 4

P.A. (4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, 60)