Question

os pontos médios dos segmentos de extremidades A(1, 6) e B(5, 4), C(-1, -7) e D(3, -5), E(-4, -3) e F(-2, -5) sao:

Answer 1

$Ponto~~m\'edio=( \frac{x_A+x_B}{2} , \frac{y_A+y_B}{2} ) \\ \\ A(1,6)~~e~~B(5,4) \\ \\ Pm_{AB}=( \frac{1+5}{2} , \frac{6+4}{2} ) \\ \\ Pm_{AB}}= (\frac{6}{2} , \frac{10}{2} ) \\ \\ Pm_{AB}=(3,5)$
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$C(-1-7)~~e~~D(3,-5) \\ \\ Pm_{CD}=( \frac{-1+3}{2} , \frac{-7-5}{2} ) \\ \\ Pm_{CD}=( \frac{2}{2} ,- \frac{12}{2} ) \\ \\ Pm_{CD}=(1,-6)$ 

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$E(-4-3)~~e~~F(-2-5) \\ \\ Pm_{EF}=( \frac{-4-2}{2} , \frac{-3-5}{2} ) \\ \\ Pm_{EF}=(- \frac{6}{2} ,- \frac{8}{2} ) \\ \\ Pm_{EF}=(-3,-4)$ 

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Letra  D