Question

TEOREMA DE PITÁGORAS
me ajudem

Answer 1

(3x - 10)² + (x + 9)² = (2x + 5)²
(9x² - 30x - 30x + 100) + (x² + 9x + 9x + 81) = (4x² + 10x + 10x + 25)
9x² - 60x + 100 + x² + 18x + 81 = 4x² + 20x + 25
9x² + x² -60x + 18x + 100 + 81 = 4x² + 20x + 25
10x² - 42x + 181 = 4x² + 20x + 25
10x² - 4x² -42x -20x + 181 - 25 = 0 
6x² - 62x + 156 = 0 
3x² - 31x + 78 = 0 

$\Delta = b^2 - 4ac \\ \Delta = (-31)^2 - 4(3)(78) \\ \Delta = 961 - 936 \\ \Delta = 25 \\ \\ \\ x = \frac{-b \pm \sqrt{\Delta}}{2a} \\ \\ x = \frac{-(-31) \pm \sqrt{25}}{2(3)} \\ \\ x = \frac{31 \pm 5}{6} \\ \\ x_1 = \frac{31 + 5}{6} = \frac{36}{6} = 6 \\ \\ x_2 = \frac{31 - 5}{6} = \frac{26}{6} = \frac{13}{3}$