Question

5y ao quadrado + 2y=0

Answer 1

5y²+2y=0
a=5
b=2
C=0
∆=b²-4ac
=2²-4(5.0)
∆=4
y=-b+-√∆/2a
y=-2+-√4/2.5
y=-2+-2/10
¹y=-2+2/10=0
²y=-2-2/10=-4/10=-2/5

Answer 2

$5y {}^2 +{2} y = 0$
$y(5y + 2) = 0$
$y = 0$
$5y + 2 = 0$
$5y = - 2$
$y = \frac{ - 2}5$