Question

como resolver x2 – 4x + 3 = 0

Answer 1

$x^2 - 4x + 3 = 0$

Resolvendo por Bháskara:

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1, b=−4, c=3

Δ=b²−4ac
Δ=(−4)²−4*(1)*(3)
Δ=16−12
Δ=4

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-4) \pm \sqrt{4}}{2*1} \\ \\ \\ x = \dfrac{4 \pm 2}{2} \\ \\ \\ x' = \dfrac{4 + 2}{2} \\ \\ \\ x' = \dfrac{6}{2} \\ \\ \\ x' = 3 \\ \\ \\ x' = \dfrac{4 - 2}{2} \\ \\ \\ x' = \dfrac{2}{2} \\ \\ \\ x' = 1$


S = {3, 1]