• Matéria: Matemática
  • Autor: JPM2017
  • Perguntado 8 anos atrás

Inequação do 2 grau
X²-7x ≤ 2x-14

Respostas

respondido por: mimafsouzap82orh
1
x^{2} - 7x \leqslant 2x - 14 \\ {x}^{2} - 7x - 2x \leqslant - 14 \\ {x}^{2} - 9x \leqslant - 14 \\ {x}^{2} - 9x + 14 \leqslant 0 \\ resolvendo \: com \: baskara
delta = b^{2} - 4.a.c
[tex]delta = -9^{2} - 4.1.14 \\ delta = 81 - 56 \\ delta = 25[tex]
respondido por: lavinnea
0
 x^{2} -7x \leq 2x-14 \\  \\  x^{2} -7x-2x+14 \leq 0 \\  \\  x^{2} -9x+14=0 \\  \\ a=1 \\ b=-9 \\ c=14 \\  \\ \Delta=b^2-4ac \\ \Delta=(-9)^2-4(1)(14) \\ \Delta=81-56 \\ \Delta=25 \\  \\ x= \frac{-b\pm \sqrt{\Delta} }{2a} = \frac{-(-9)\pm \sqrt{25} }{2} = \frac{9\pm5}{2}  \\  \\ x'= \frac{9-5}{2} = \frac{4}{2} =2 \\  \\ x"= \frac{9+5}{2} = \frac{14}{2} =7~

++++\bullet^2----\bullet^7++++ \\ ~~~m/a~~~~~~~~~~c/a~~~~~~~~~~~~m/a \\  \\  \\ como~~pediu~~ \leq ~0 \\  \\ S=\{x\in R/2 \leq x \leq 7\}
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