Question

Seja a função. Definida por f(x)=3x+1

A=f(-2÷3)+f(-1÷2)

Answer 1

$f ({ \frac{ - 2}{3} } ) = 3 \times \frac{ - 2}{3} + 1 \\ f ({ \frac{ - 2}{3} } ) = \frac{ - 6}{3} + 1 \\ f ({ \frac{ - 2}{3} } ) = - 2 + 1 \\ f ({ \frac{ - 2}{3} } ) = - 1$
$f( \frac{ - 1}{2} ) = 3 \times \frac{ - 1}{2} + 1 \\ f( \frac{ - 1}{2} ) = \frac{ - 3}{2} + 1 \\ f( \frac{ - 1}{2} ) = \frac{ - 3 + 2}{2} \\ f( \frac{ - 1}{2} ) = \frac{ - 1}{2}$
$A=f( \frac{ - 2}{3} )+f( \frac{ - 1}{2} ) \\ A = - 1 + \frac{ - 1}{2} \\ A = \frac{ - 2 - 1}{2} \\ A= \frac{ - 3}{2}$