Question

determine as raizes das funcoes a) y=x²-6x-3 B) y=x²-3x-10 alguem mi ajuda

Answer 1

$a) \ x^2-6x-3\\ \delta=(-6)^2-4*1*-3\\ \delta=36+12=48\\\\ x= \frac{6 \frac{+}{-}4\sqrt{3} }{2}\\\\ x_1=3+2\sqrt{3} \ \ \ \ \ x_2=3-2\sqrt{3}$

$b) x^2-3x-10\\ x_1=5 \ \ \ \ \ x_2=-2$