• Matéria: Matemática
  • Autor: gecileneguedesl
  • Perguntado 9 anos atrás

sendo J={32:[(9-3):2+5]+3}.2 e R={[(42:6+1):2+1].3-7}:4.3+1 , qual o valor de J:R ?

Respostas

respondido por: FioxPedo
12

J = {32 ÷ [(9 - 3) ÷ 2 + 5] + 3} × 2

J = {32 ÷ [6 ÷ 2 + 5] + 3} × 2

J = {32 ÷ [3 + 5] + 3} × 2

J = {32 ÷ 8 + 3} × 2

J = {4 + 3} × 2

J = 7 × 2

J = 14

R = {[(42 ÷ 6 + 1) ÷ 2 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {[(7 + 1) ÷ 2 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {[8 ÷ 2 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {[4 + 1] × 3 - 7} ÷ 4 × 3 + 1

R = {5 × 3 - 7} ÷ 4 × 3 + 1

R = {15 - 7} ÷ 4 × 3 + 1

R = 8 ÷ 4 × 3 + 1

R = 2 × 3 + 1

R = 6 + 1

R = 7

J ÷ R = 14 ÷ 7

J ÷ R = 2

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