Question

resolva usando bhaskara

Answer 1

Olá!!!

Resoluçao!!!

4y² - 3y - 1 = 0

a = 4, b = - 3, c = - 1

∆ = b² - 4ac
∆ = ( - 3 )² - 4 • 4 • ( - 1 )
∆ = 9 + 16
∆ = 25

bhaskara :

y = - b ± √∆ / 2a
y = - ( - 3 ) ± √25 / 2 • 4
y = 3 ± 5 / 8
y' = 3 + 5 / 8 = 8/8 = 1
y" = 3 - 5 / 5 = - 2/8 : 2 = - 1/4

S = { - 1/4 , 1 }

Espero ter ajudado!!!

Answer 2

$4 {y}^{2} - 3y - 1 = 0$

$a = 4, \: b = ( - 3), \: c = ( - 1)$

∆ = b² - 4ac

∆ = (- 3)² - 4 × 4 × (- 1)

∆ = 9 + 16

∆ = 25


y = - b ± √∆ /2a

y = - (- 3) ± √25 /2 × 4

y = 3 ± 5/ 8


y¹ = 3 + 5/8 = 8/8 = 1

y² = 3 - 5/8 = - 2/8 (÷ 2) = - 1/4


S = {- 1/4, 1}