Question

Resolva a eq x²-2x+3=-12+6x

Answer 1

${x}^{2} - 2x - 6x + 3 + 12 = 0 \\ {x}^{2} - 8x + 15 = 0 \\ delta = {(-8)}^{2} - 4 \times 1 \times 15 \\ delta= 64 - 60 \\ delta= 4 \\ \\ x1 = \frac{ - ( - 8) + \sqrt[2]{4} }{2 \times 1} = \\ x1 = \frac{8 + 2}{2} = \\ x1 = \frac{10}{2} = 5 \\ x1 = 5 \\ \\ x2 = \frac{ - ( - 8) - \sqrt{4} }{2 \times 1} = \\ x2 = \frac{8 - 2}{2} = \\ x2 = \frac{6}{2} = 3 \\ x2 = 3$
espero ter ajudado ❤️

Answer 2

x² - 2x + 3 = - 12 + 6x
x² - 2x - 6x + 3 + 12 = 0
x² - 8x + 15 = 0

a = 1
b = -8
c = 15

Δ = b² - 4 .a . c
Δ = (-8)² -4 . 1 . (15)
Δ = 64 -60
Δ = 4

$\mathtt{\dfrac{-b+-~\sqrt{\Delta}}{2~.~a}~~=~~\dfrac{-(-8)+-~\sqrt{4}}{2~.~1}~~=~~\dfrac{8+-~2}{2}} \\ \\ \\ \mathtt{x' =\dfrac{8+2}{2}~~=~~\dfrac{10}{2}~~=~~ 5} \\ \\ \\ \mathtt{x'' = \dfrac{8-2}{2}~~=~~-\dfrac{6}{2}~~=~~3}$

Resposta: S{ 3   e 5  }