Question

Calcule essa equação.

ײ+3×-4=o

Answer 1

delta= 3^2-4.1.(-4)
9+16
D=25

bhaskara=
-3+-raiz quadrada de 25.
dividido por 2.

x'= -3+5/2
+1
x''= -3-5/2
-4

Answer 2

x² +3x - 4 = 0

a = 1
b = 3
c = -4

Δ = b² - 4 .a . c
Δ = 3² -4 . 1 . (-4)
Δ = 9 + 16
Δ = 25

$\mathtt{\dfrac{-b+-~\sqrt{\Delta}}{2~.~a}~~=~~\dfrac{-3+-~\sqrt{25}}{2~.~1}~~=~~\dfrac{-3+-~5}{2}} \\ \\ \\ \mathtt{x' =\dfrac{-3+5}{2}~~=~~\dfrac{2}{2}~~=~~ 1} \\ \\ \\ \mathtt{x'' = \dfrac{-3-5}{2}~~=~~-\dfrac{8}{2}~~=~~-4}$

Resposta: S{ -4   e 1 }