Question

Dado a função f(2)=2x²-12x+16 sendo f(x)=4 calcule delta e baskara

Answer 1

2x²-12x+16=0                 a=2,  b=-12,      c= 16

Δ=(-12)²-4.2.16                                  x'=12+4/2           x''=12-4/2
Δ=144-128                                         x'=16/2               x''=8/2
Δ=16                                                  x'=8                     x''=4
x=-(-12)+-√16/2.2x=12+-4/2