Question

(6a^2+10ab+b^2) . (-3/4a)

^2=ao quadrado

Answer 1

(6a^{2} . -3/4a) + (10ab . -3/4a) + (b^{2} . -3/4a)

= (-18a^{3} /4) + (-30a^{2} b /4) + (-3a b^{2} /4)

= -18a^{3} /4 - 30a^{2} b /4 - 3a b^{2} /4.

Boa noite! c: