Question

Alguém pode me ajudar por favor?
Obrigada desde já
(Somente o 4)

Answer 1

a)
$x {}^{2} + 4x + 3$
b)
$2x {}^{3} + 2x {}^{2} - x + 5$
c)
$4x {}^{2} + 6x + 2$
a)A+B+C

(Tem que arrumar)

$x {}^{2} + 2x {}^{2} + 4x {}^{2} + 4x - x + 6x + 3 + 5 + 2$
some os termos semelhantes
resposta=
$2 {x}^{3} + 5x {}^{2} + 9x + 10$
b)b.c
$2 {x}^{3} + 2x {}^{2} - x + 5 \times 4x {}^{2} + 6x + 2 \\ 2x {}^{3} + 2x {}^{2} - x + 20x {}^{2} + 6x + 2 \\ 2x {}^{3} + 22x {}^{2} - x + 6x + 2 \\ 2x {}^{3} + 22x {}^{2} + 5x + 2$
resposta:
$2x {}^{3} + 22x {}^{2} + 5x + 2$
c)A-C
$x {}^{2} + 4x + 3 - 4x {}^{2} + 6x + 2 \\ - 3x {}^{2} + 4x + 3 + 6x + 2 \\ - 3x {}^{2} + 10x + 3 + 2 \\ - 3x {}^{2} + 10x + 5$
resposta:
$- 3x {}^{2} + 10x \times 5$
d)a.(c-b)
$x {}^{2} + 4x + 3(4x {}^{2} + 6x + 2 - 2x {}^{3} + 2x {}^{2} - x + 5) \\ x {}^{2} + 4x + 3(6x {}^{2} + 6x + 2 - 2x {}^{3} - x + 5) \\ x {}^{2} + 4x + 3(6x {}^{2} + 5x + 2 - 2x {}^{3} + 5) \\ x {}^{2} + 4x + 3 (6x {}^{2} + 5x + 7 - 2x {}^{3} )$
(chuveirinho)
$x ^{2} + 4x + 18x {}^{2} + 15x + 21 - 6x {}^{3} \\ 19x {}^{2} + 4x + 15 + 21 - 6x {}^{3} \\ 19x {}^{2} + 19x + 21 - 6x^{3}$
(Reorganize)
$- 6x {}^{3} + 19x {}^{2} + 19x + 21$
resposta:
$- 6x {}^{2} + 19x {}^{2} + 19x \times 21$