Question

qual a formula minina e a formula molecular de 48,48% de C, 5,05% de H, 14,14% de N, 32,32% de O massa molar=198g/mol

Answer 1

primeiramente calculamos a fórmula molecular:

C => 198.0,4848 ≈ 96g
nC => 96/12 = 8

H => 198.0,0505 ≈ 10g
nH => 10/1 = 10

N => 198.0,1414 ≈ 28g
nN=> 28/14 = 2

O => 198.0,3232 ≈ 64g
nO => 64/16 = 4

FM → C8H10O4N2
fm → C4H5O2N