Question

X ao quadrado +12x-12=1

Answer 1

$x^{2}$+12x-12=-1
$x^{2}$+12x-12+1=0
$x^{2}$+12x-11=0
Δ=$b^{2}$-4*a*c
Δ=$12^{2}$-4*1*(-12)
Δ=144+48=192

$x= \frac{-b+- \sqrt{Δ}}{2*a}$
$x= \frac{-12+- \sqrt{192} }{2}$
$\frac{-12+-8 \sqrt{3}}{2}$
$x1= \frac{-12+8 \sqrt{3} }{2}$=-6+4$\sqrt{3}$
x2= \frac{-12-8 \sqrt{3} }{2} [/tex]=-6-4$\sqrt{3}$