Question

Determinar o angulo entre os vetores u=(3,-1,4) e v=(-2,2,3)

Answer 1

Alpha=(3,-1,4)
Beta=(-2,2,3)

Â=|n1.n2|/|n1|.|n2|

|n1.n2|=|(3,-1,4).(-2,2,3)|
|N1.N2|=|-6,-2,7|
|N1.N2|=-1


|N1|=V3^2+(-1)^2+4^2
|N1|=V9+1+16
|N1|=V26

|N2|=V-2^2+2^2+3^2
|N2|=V4+4+9
|N2|=V17

|N1|.|N2|
V26.V17
V442=21,02379

CosÂ=-1/21,02379
CosÂ=-0.04756

Â=Cos^-1 0,04756
Â=92,72

Obs: "^" siginifica "elevado"
"V" significa "raiz quadrada"

espero ter ajudado