Question

considerando log 2= 0.3010 e log 3= 0, 4771, caucule log de
$\sqrt[3]{48 }$

Answer 1

Bom dia 

log(³√48) = log(48)/3 

48  2
24  2
12  2
  6  2
  3  3
  1

48 = 2^4 * 3

log(48) = 4log(2) + log(3)
log(48) = 4*0.301 + 0.4771 = 1.6811

log(³√48) = log(48)/3 = 1.6811/3 = 0.56036