Question

obtenha a equaçao da reta que passe pelos pontos
A- (2, 3) e (3, 5)
B- (-1, 5) e (2, 10)

Answer 1

primeiro calcular o coeficiente angular
m=3-2/5-3= 1/2
y-y1= m(x-x1)
y-3= 1/2(x-2)
2(y-3)= x-2
2y-6=x-2
2y-x-6+2=0
2y-x-4=0
-x+2y-4=0
x-2y+4=0


m= 2-(-1)/10-5= 2+1/5= 3/5

y- (-1)= 3/5(x-5)
5(y+1)=3(x-5)
5y+5=3x-15
-3x+5y+5+15=0
-3x+5y+20=0
3x-5y-20=0