Question

Se f(x)=2x^3, entao os valores de f(0);f(-1);f(2);f(-2) e -F(1/2) sao

Answer 1

f(x)=2.x³
f(0)=2.0³=2.0=0

f(-1)=2.(-1)³=2.(-1)=-2

f(2)=2.2³=2.8=16

f(-2)=2.(-2)³=2.(-8)=-16

f(1/2)=2.(1/2)³=2.(1/8)=2/8=1/4