Question

o valor das raízes da equação x^2+3x-10=0?



obrigada!!

Answer 1

$x^2+3x-10=0$.

Coeficientes:
$a=1$;
$b=3$;
$c=-10$.

Bhaskara:

Δ$=b^2-4ac$ =>
Δ$=3^2-4.1.(-10)$ =
Δ$=9+40$ =>
Δ$49$.

$x=\frac{-b\frac{+}{-}\sqrt{DELTA}}{2a}$ =>
$x=\frac{-3\frac{+}{-}\sqrt{49}}{2.1}$ =>
$x=\frac{-3\frac{+}{-}7}{2}$.

$x_{1}=\frac{-3+7}{2}$ =>
$x_{1}=\frac{4}{2}$ =>
$x_{1}=2$.

$x_{2}=\frac{-3-7}{2}$ =>
$x_{2}=\frac{-10}{2}$ =>
$x_{2}=-5$.

S = ( -5, 2 ).