Question

Quais são as raízes da equação ײ+10×+16=0

Answer 1

a=1 b=10 c=16


Δ $=b^-4ac$
Δ = $(10)^2-4(1)(16)$
Δ = $100-64$ 
Δ = 36
$x_{1} = \frac{-b+ \sqrt{Δ}}{2a}$



$\frac{-10+ \sqrt{36} }{2(1)}$

$\frac{-10+6}{2}$

$\frac{-4}{2}$

$x_{1} = -2$

$x_{2} = \frac{-b- \sqrt{Δ} }{2a}$

$\frac{-10- \sqrt{36} }{2(1)}$

$\frac{-10-6}{2}$

$\frac{-16}{2}$

$x_{2} = -8$