Question

a soluçao da equação 3x²-7x+4=0

Answer 1

basta usar Bhaskara : $\frac{-b+- \sqrt{b^2-4.a.c} }{2.a} ..... \frac{-7+- \sqrt{49-48} }{2.3}$

$\frac{-7-+1}{6}$

x¹=1 x²=$\frac{8}{6}.... \frac{4}{3}$

Answer 2

$3x^2 - 7x + 4 = 0$

Resolvendo por Bháskara

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=3, b=−7, c=4

Δ=b²−4ac
Δ=(−7)²−4*3*4
Δ=49−48
Δ=1

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-(-7) \pm \sqrt{1}}{2*3} \\ \\ \\ x = \dfrac{7 \pm 1}{6} \\ \\ \\ x' = \dfrac{7 + 1}{6} \\ \\ \\ x' = \dfrac{8}{6} \\ \\ \\ x' = \dfrac{4}{3} \\ \\ \\ x'' = \dfrac{7 - 1}{6} \\ \\ \\ x'' = \dfrac{6}{6} \\ \\ \\ x' = 1$


S = { $\dfrac{4}{3} , \ \ 1$}